Bug 1147283 - Replace mozpack.path with mozpath. r=mshal

Back when mozpack.path was added, it was used as:

  import mozpack.path
  mozpack.path.func()

Nowadays, the common idiom is:

  import mozpack.path as mozpath
  mozpath.func()

because it's shorter.

$ git grep mozpath\\. | wc -l
423
$ git grep mozpack.path\\. | wc -l
123

This change was done with:
$ git grep -l mozpack.path\\. | xargs sed -i 's/mozpack\.path\./mozpath./g'
$ git grep -l 'import mozpack.path$' | xargs sed -i 's/import mozpack.path$/\0 as mozpath/'
$ (pat='import mozpack.path as mozpath'; git grep -l "$pat" | xargs sed -i "1,/$pat/b;/$pat/d")
This commit is contained in:
Mike Hommey
2015-03-25 15:05:28 +09:00
parent 969d697ade
commit 2e51d2ef87
23 changed files with 138 additions and 141 deletions

View File

@@ -10,7 +10,7 @@ from mozpack.files import (
BaseFile,
Dest,
)
import mozpack.path
import mozpack.path as mozpath
import errno
from collections import (
Counter,
@@ -41,7 +41,7 @@ class FileRegistry(object):
partial_paths = []
partial_path = path
while partial_path:
partial_path = mozpack.path.dirname(partial_path)
partial_path = mozpath.dirname(partial_path)
if partial_path:
partial_paths.append(partial_path)
return partial_paths
@@ -73,13 +73,13 @@ class FileRegistry(object):
'''
if '*' in pattern:
return [p for p in self.paths()
if mozpack.path.match(p, pattern)]
if mozpath.match(p, pattern)]
if pattern == '':
return self.paths()
if pattern in self._files:
return [pattern]
return [p for p in self.paths()
if mozpack.path.basedir(p, [pattern]) == pattern]
if mozpath.basedir(p, [pattern]) == pattern]
def remove(self, pattern):
'''